Question

Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0)

Answer 1

`Perimeter\ = AB+BC+AC\\\\ AB=√((x_B-x_A)^2+(y_B-y_A)^2)=√((0+3)^2+(4-0)^2)=\\√(3^2+4^2)=√(9+16)=√(25)=5\\\\ BC=√((x_C-x_B)^2+(y_C-y_B)^2)=√((3-0)^2+(0-4)^2)=\\√(3^2+(-4)^2)=√(9+16)=√(25)=5\\\\\ AC=√((x_C-x_A)^2+(y_C-y_A)^2)=√((3+3)^2+(0-0)^2)=\\√(6^2+0^2)=√(36+0)=√(36)=6\\\\Perimeter=5+5+6=16`