Question

How to find the area of the 45-45-90 triangle with a hypotenuse of 24?

Answer 1

`45^o-45^o-90^o\ triangle\ is\ a\ half\ of\ the\ square\ (look\ at\ he\ picture).\\\\The\ square\ is\ a\ rhombus\\then\ area\ equal\ the\ half\ of\ multiply\ diameters:\\\\A_{\fbox{}}=(d^2)/(2)\\\\A_\Delta=(1)/(2)A_{\fbox{}}\Rightarrow A_\Delta=(1)/(2)\cdot(d^2)/(2)=(d^2)/(4)\Rightarrow A_\Delta=(24^2)/(4)=(576)/(4)=144.`

Answer 2

The area of a triangle is 1/2(base x height) .

The two legs of this triangle are equal. If you position it properly,
one of them is the base, and the other one is the height.

Since it's a right triangle, A² + B² = C²

But A = B and C = 24 .

2A² = (24)²

A² = (24)² / 2

But since A=B, A² is also (base x height) of the triangle.
Area is just 1/2 of it.

Area = 1/2(24²/2) = (24)²/4 = (24/2)² = (12)² = 144 .