We are asked to determine which transformation will result in the image being entirely in the I quadrant. This means that we need to determine which transformation will result in each image point of each vertex (x',y') being x' >0 and y'>0.
we can use the following transformation:
A rotation of 90° counterclockwise around the point Q = (4, 12).
The law associated with this transformation is:
Where (a,b) is the point around which the rotation is made, that is (a, b) = (4, 12). Replacing we get:
Solving the operations:
Now we transform each vertex. For vertex S = (-3,-7). replacing in the transformation:
Solving the operation:
Since both coordinates are positive, this vertex is in the first quadrant.
For vertex P = (-3, 7). Replacing:
Therefore P' is in the first quadrant.
For vertex Q = (4,12)