Question

Find two consecutive numbers whose squares differ by 17

Answer 1

Let

x---------> the first number

x+1------> the second number

we know that

`(x+1)^(2) -x^(2) =17\\ x^(2) +2x+1-x^(2) =17\\ 2x+1=17\\ 2x=16\\ x=8`

so

`x=8\\ x+1=9`

therefore

the answer is

the numbers are

`8,9`