Find two consecutive numbers whose squares differ by 17

asked Mar 9, 2016 115k views

1 vote

by Ro

6.9k points

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6 votes

Let

x---------> the first number

x+1------> the second number

we know that

$(x+1)^(2) -x^(2) =17\\ x^(2) +2x+1-x^(2) =17\\ 2x+1=17\\ 2x=16\\ x=8$

$x=8\\ x+1=9$

therefore

the answer is

the numbers are

Satesh answered Mar 13, 2016

8.2k points

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