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Find the exact value by using a half-angle identity.

sin 22.5degrees
show your work. thanks!

User DDR
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1 Answer

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sin( ( \alpha )/(2))=\sqrt{ (1-cos\alpha)/(2) }\\\alpha=45^\circ\\ sin(22,5)=\sqrt{ (1-cos45)/(2) }\\ sin(22,5)=\sqrt{ (1-(\sqrt2)/(2))/(2) }\\ sin(22,5)=\sqrt{ (2-\sqrt2)/(2)*(1)/(2) }\\sin(22,5)=\sqrt{ (2-\sqrt2)/(4) }
User Trauer
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