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What is the value of root 12+root 12+root12.... ...............to infinite
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What is the value of root 12+root 12+root12....
...............to infinite

User ENepper
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1 Answer

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x=root(12+root(12+root(...)))
x^2=12+root(12+root(12+root(...)))
x^2=12+x
x^2-x-12=0
(x+3)(x-4)=0
X=4
User Shareena
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