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Which linear equation describes the line passing through point (10, 3) and has a y-intercept at (0, -1)?10y = -3x +y = -x +y=2- 1= 5*-y=31-x-13*-52

User Rufanov
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1 Answer

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Answer: y = 2x/5 - 1

Step-by-step explanation:

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

The formula for calculating slope is expressed as

m = (y2 - y1)/(x2 - x1)

The given points are (0, -1) and (10, 3). thus,

x1 = 0, y1 = - 1

x2 = 10, y2 = 3

m = (3 - - 1)/(10 - 0) = (3 + 1)/10 = 4/10 = 2/5

By substituting m = 2/5 and c = - 1 into the slope intercept equation, the equation of the line is

y = 2x/5 - 1

User Barankin
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