Question

What are the first three terms of the sequence a1 = 3 and an = 2(an-1)^2? I thought the answer was 3,18,32 but that's not an option! help????

Answer 1

a1=3
a2=2(3^2)=18
a3=2(18^2)=648

Answer 2

3,18,648

Explanation:

We are asked to find out the first three terms of the sequence.

Recurring formula is given as

`a_(n) =2(a_(n-1) ^2)`

Since I term = 3

`a_(2) =2(a_(1))^2=2(3^2)=18`

Applying the same rule,

third term

=
`a_(3) =2(a_(2))^2\\=2(18^2)\\=648`

Like this we can find out any number of terms using this recursive formula