Question

Graph the function Plot any five points on the graph.

Answer 1

Given the equation,

`y=-(11)/(8)x^3`

Let us pick 5 points starting from x = 0 to x = 4

Having picked from point x = 0, let us solve for the corresponding y-values.

When x = 0,

`\begin{gathered} y=-(11)/(8)*0^3=-(11)/(8)*0=0 \\ \therefore y=0 \end{gathered}`

So when x = 0, y = 0

When x = 1

`\begin{gathered} y=-(11)/(8)*1^3=-(11)/(8)*1=-(11)/(8)=-1.375 \\ \therefore y=-1.375 \end{gathered}`

So when x = 1, y = -1.375

When x = 2,

`\begin{gathered} y=-(11)/(8)*2^3=-(11)/(8)*8=-11 \\ \therefore y=-11 \end{gathered}`

So when x = 2, y = -11

When x = 3

`\begin{gathered} y=-(11)/(8)*3^3=-(11)/(8)*27=-37.125 \\ \therefore y=-37.125 \end{gathered}`

So when x = 3, y = -37.125

When x = 4

`\begin{gathered} y=-(11)/(8)*4^3=-(11)/(8)*64=-11*8=-88 \\ \therefore y=-88 \end{gathered}`

So when x = 4, y = -88.

Let us now plot the graph