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Simplify sin(3x+13)=cos(4x)

User JsonV
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1 Answer

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Sin(3×+13)=sin(pi/2-4×)
3x+13 =pi/2 -4× or 3×+13 =pi-pi/2 + 4×
7× = pi/2 - 13 +k2pi or -× = pi/2 +k2pi
× = pi/14 - 13/7 k2pi/7 or X = -pi/2 + kpi

User Yancey
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