117k views
2 votes
the perimeter of a rectangle is 44 m. If the width were doubled and the length were increased by 8 m, the perimeter would be 76 m. What is the length of the rectangle

User Lbstr
by
8.2k points

1 Answer

3 votes
Let us assume the length of the first rectangle = x meter
let us assume the width of the first rectangle = y meter
Perimeter of the first rectangle = 44 meter
we already know
Perimeter of a rectangle = 2 (Length + Width)
Then in the case of the first rectangle we get
44 = 2(x + y)
44/2 = x + y
x + y = 22
y = 22 - x
Now coming to the case of the second rectangle
The length of the second rectangle = x + 8
The width of the second rectangle = 2y
Perimeter of the second rectangle = 76 meter
then
76 = 2[(x + 8) + 2y]
76/2 = x + 8 + 2y
38 = x + 2y + 8
x + 2y = 38 - 8
x + 2y = 30
Now we replace the value of y that we found from the first equation. Then
x + 2(22 - x) = 30
x - 2x + 44 = 30
-x = 30 - 44
-x = -14
x = 14
So the length of the first rectangle is 14 meters.
User Royhowie
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories