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Graph the equation y = 2x – 3 using slope and y-intercep 5 4 3 2 0

User Ani Menon
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1 Answer

13 votes
13 votes

Here, we want to graph the line y = 2x-3 using slope and the y-intercept

The value of the slope if positive or negative will tell us the direction of the graph whether rising or falling while the y-intercept will tell us the point at which the graph crosses the y-axis

Mathematically, we can have the equation representing a linear function as;


y\text{ = mx + b}

where m represents the slope and b represents the y-intercept

If the slope is positive as in the case with this question (+2), then the graph is a rising graph.

To complete the graph, we need to identify the y-intercept which is -3 in this case

So to graph the line, we locate the point -3 on the y-axis then we draw a rising line through this point

To get a point on the x-axis, we will need the value of the x-axis

The value on the y-axis is 0 at this point


\begin{gathered} 0\text{ = 2x - 3} \\ \\ 2x=\text{ 3} \\ \\ x\text{ = }(3)/(2) \\ \\ x\text{ = 1.5} \end{gathered}

An overview is shown below;

Graph the equation y = 2x – 3 using slope and y-intercep 5 4 3 2 0-example-1
User Lawrence
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2.6k points
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