this is a 2x2 system of equations.
Let:
-2x = 4y + 6 (1)
and
2(2y+3) = 3x - 5 (2)
Let's rewrite (1) as:
2x + 4y = -6 (1)
and (2) as:
3x - 4y = 11 (2)
Now, from (1)
Let's solve for x:
2x + 4y = -6
Subtract 4y from both sides:
2x + 4y - 4y = -6 - 4y
2x = -6 - 4y
Divide both sides by 2:
2x/2 = (-6 - 4y)/2
x = -3 - 2y (3)
Replacing (3) into (2)
3x - 4y = 11
3(-3 - 2y) - 4y = 11
Using distributive property:
-9 - 6y - 4y = 11
Add like terms:
-10y - 9 = 11
Add 9 to both sides:
-10y - 9 + 9 = 11 + 9
-10y = 20
Divide both sides by -10:
(-10y)/-10 = 20/-10
y = -2
Finally, replace the value of y into (3)
x = -3 - 2y
x = -3 - 2(-2)
x = -3 + 4
x = 1
Therefore the solution is :
x= 1 and y=-2
(x,y) = (1,-2)