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Balance the redox reaction:Cr2O7^2-+C2O4^2---->Cr^3++CO2

User Pawel Czyz
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1 Answer

12 votes
12 votes

First let's discover which element is oxidizing and which is reducing

So first let's rewrite the equation here:

Cr2O7^2- + C2O4^-2----> Cr^3+ + CO2

Reactant side:

oxidation state for Cr:

2x + (-2x7) = -2

x = +6

oxidation state for C:

2x + [4x(-2)] = -2

x = +3

Product side:

Cr - +3

oxidation state for C:

x + [2x(-2)] = 0

x = +4

User Okwme
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