Question

Hello I need help with this question pleaseFind the equation of the line containing the given points (3, -2) and (-4, -8)

Answer 1

To find the equation of a line, the formula is

`(y-y_1)/(x-x_1)=(y_2-y_1)/(x_2-x_1)`

Where

`\begin{gathered} (x_1,y_1)=(3,-2) \\ (x_2,y_2)=(-4,8) \end{gathered}`

Substitute the values of the variable

`\begin{gathered} (y-(-2))/(x-3)=(-8-(-2))/(-4-3) \\ (y+2)/(x-3)=(-8+2)/(-7) \\ (y+2)/(x-3)=(-6)/(-7) \end{gathered}`
`\begin{gathered} Crossmultiply \\ -7(y+2)=-6(x-3) \\ -7y-14=-6x+18 \\ 6x-7y-18-14=0 \\ 6x-7y-32=0 \end{gathered}`

Hence, the equation is

`6x-7y-32=0`