Question

Subtract seven more than twice a number from the square of one-third of the number you get zero

Answer 1

We will first translate this word problem into numerical expression.
Subtract seven more than twice a number from the square of one-third of the number and you get zero can be written into this form;
Let x = number

`((1)/(3)) ^(2) - (2x + 7) = 0`

`(1)/(9) x^(2) - 2x - 7 = 0`

`9( (1)/(9) x^(2) -2x - 7) = 9 (0)`

`x^(2) - 18x - 63 = 0`

`(x - 21)(x + 3) = 0`

Therefore, the value of x are
x - 21 = 0 and x + 3 = 0
x = 21 x = -3

Answer: {21, -3}