Question

16. A gas occupies a volume of 777 mL at a temperature of 318 K and a pressure of 299 mm Hg. If the volume remains constant and the temperature is doubled, what will its pressure be?

Answer 1

598 mmHg

Step-by-step explanation

Given

Volume of the gas = 777 mL

Initial temperature, T₁ = 318 K

Initial pressure, P₁ = 299 mmHg

Since the temperature is double, then the final temperature = 2 x 318 K = 636 K

What to find:

The final pressure of the gas when its temperature is doubled.

Step-by-step solution:

Since the volume remains constant, then the final pressure of the gas can be calculated using Amonton's law formula below:

`\begin{gathered} (P_1)/(T_1)=(P_2)/(T_2) \\ \\ \Rightarrow P_2=(P_1T_2)/(T_1) \end{gathered}`

Putting the values of the parameters into the formula, we have

`P_2=(299mmHg*636K)/(318K)=598\text{ }mmHg`

The final pressure of the gas when its temperature is doubled is 598 mmHg