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Let f(x)=2x-3 and g(x)= -x^2-1 find ( g o f) (x)

User Skaue
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2 Answers

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g \circ f=-(2x-3)^2-1=-(4x^2-12x+9)-1=\\ =-4x^2+12x-9-1=-4x^2+12x-10\\
User Ruchir Gupta
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f(x)=2x-3\ \ \ and\ \ \ g(x)= -x^2-1\\\\( g \circ f) (x)=g\bigg(f(x)\bigg)=g\bigg(2x-3\bigg)=-(2x-3)^2-1=\\\\=-(4x^2-12x+9)-1=-4x^2+12x-9-1=-4x^2+12x-10
User Cian
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