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X + 2y - 12= 03x + 2y - 4 =0 Solve the following linear system GRAPHICALLY on the given graphs.

User Pontomedon
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Equations given:


x+2y-12=0
3x+2y-4=0

The solution of a system of equations is the point at which the graphs intersect each other. If we graph the function, we will obtain the following graph:

where the blue line represents the first equation and the red line the second equation. Based on that, we evaluate the value for x and y in which the functions collide:

Answer: (-4, 8)

X + 2y - 12= 03x + 2y - 4 =0 Solve the following linear system GRAPHICALLY on the-example-1
X + 2y - 12= 03x + 2y - 4 =0 Solve the following linear system GRAPHICALLY on the-example-2
User Jeff Pratt
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