Question

When lithium reacts with bromine to form the compound LiBr each lithium atom

(1) gains one electron and becomes a negatively charged ion
(2) gains three electrons and becomes a negatively charged ion
(3) loses one electron and becomes a positively charged ion
(4) loses three electrons and becomes a positively charged ion

Answer 1

(1) gains one electron and becomes a negatively charged ion
(2) gains three electrons and becomes a negatively charged ion
(3) loses one electron and becomes a positively charged ion
(4) loses three electrons and becomes a positively charged ion

Answer 2

Answer: (3) loses one electron and becomes a positively charged ion

Step-by-step explanation:

Lithium bromide is formed by combination of lithium cation and bromine anion.

Electronic configuration of lithium:

`[Li]=1s^22s^1`

Lithium atom will loose one electron to gain noble gas configuration and form lithium cation with +1 charge.

`[Li^+]=1s^2`

Electronic configuration of bromine:

`[Br]=[Ar]3d^(10)4s^24p^5`

Bromine atom will gain one electron to gain noble gas configuration and form bromide ion with -1 charge.

`[Br^-]=[Ar]3d^(10)4s^24p^6`

In lithium bromide, one electron from lithium metal gets transferred to bromine atom.