Investments and percentages
Sally has two investments:
x at 15% of interest
4x+$203 at 8% of interest
Each month she is receiving
0.15x+0.08(4x+$203)=0.15x+0.32x+$16.24
=0.47x+$16.24
Then, the whole year she received
=12(0.47x+$16.24)
since we know that after onw year she received $2017.03
then
$2017.03 = 12(0.47x+$16.24)
Now we just must find x
0.47x+$16.24 = $2017.03/12
= $168.085
0,47x = $168,085-$16,24
= $152,085
Therefore x = $323,58 is the amount of money of her first investment
Since the second investment's is given by 4x+$203
then the amount of money of her second investment is $1 310,56