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Need help fast what are all the solution to this problem

Need help fast what are all the solution to this problem-example-1
User Mbaydar
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2 Answers

4 votes

x^(2) - 25 = 0 \\ x^(2) = 0 + 25 \\ x^(2) = 25 \\ x = \pm √(25) \\ \boxed{x = \pm 5}

correct alternatives : C , D
User TwoLeftFeet
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3 votes
x² - 25 = 0

The left side is the difference of 2 squares,
so we know right away, without any uncertainty
or sweat, that it can be written as

(x + 5) (x - 5) ,

and we know that it's equal to zero when either factor is zero.

Now let's look at the choices:

A. X = -1 Not a chance.

B. X = -3 Also no.

C. X = -5 Yes that's good; that would make the first factor zero.

D. X = 5 Yes that's good too; it would make the second factor zero.

E. X = 3 Not true. Don't know how they came up with it.

F. X = 1 Equally not true.
User Joe Block
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6.9k points