Question

aPerform the indicated operations and reduce to lowest terms. Assume that no denominator has a valueof zero.2x² x -2x2 + x - 21 8x + 16x² + 2xx - 3AnswerKeypadKeyboard Shortcuts

Answer 1

Given:

`(2x^2+x-21)/(x^2+2x)*(8x+16)/(x-3)`

To find: The reduced form

Step-by-step explanation:

Let us write it as the factored form.

`\begin{gathered} (2x^2+x-21)/(x^2+2x)*(8x+16)/(x-3)=\frac{2x^2+7x-6x-21}{x(x^{}+2)}*(8(x+2))/(x-3) \\ =\frac{x(2x^{}+7)-3(2x+7)}{x(x^{}+2)}*(8(x+2))/(x-3) \\ =\frac{(x-3)(2x+7)}{x(x^{}+2)}*(8(x+2))/(x-3) \end{gathered}`

Simplifying we get,

`(8(2x+7))/(x)`

Final answer: The simplest form is,

`(8(2x+7))/(x)`