Question

I need help with axis of symmetry this problem y=-x²+4x+3

Answer 1

x = 2

Step-by-step explanation

We want to find the axis of symmetry of the equation:

`y=-x^2\text{ + 4x + 3}`

The axis of symmetry of a quadratic equation is given as:

`\begin{gathered} \text{For:} \\ y=ax^2\text{ + bx + c} \\ \text{Axis of symmetry: } \\ x\text{ = -}(b)/(2a) \end{gathered}`

From the given equation, a = -1 and b = 4

Therefore, the axis of symmetry is:

`x\text{ = -}(4)/(2(-1))\text{ = -}(4)/(-2)\text{ = }(-4)/(-2)`

That is the axis of symmetry.