How many moles are in 17.31 g of NaHCO,?

asked Mar 24, 2022 4.8k views

8 votes

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8 votes

Answer:

0.33moles

Step-by-step explanation:

RAM of;

Na = 23, H=1, C=12, O=16

molar mass of NaHCO= 23+1+12+16= 52g/mol

mole= mass / molar mass

mole = 17.31/52

mole= 0.33moles

Consule answered Mar 31, 2022

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