Question

What is 10x^2 +79x-8

Answer 1

`10x^2+79x-8`

Factor:

The coefficient of x² is 10 and the constant term is -8, so:

`10*-8=-80`

The factors of 80 which sum to 79 are -1 and 80, hence:

`10x^2+79x-8=10x^2+80x-x-8`

Group like terms:

`10x^2+80x-x-8=8(10x-1)+x(10x-1)`

Factor 10x-1 from the previous expression:

`(10x-1)(8+x)`