Question

The Math Club sold roses and tulips this year for valentines day. The number of roses sold was 8 more than 4 times the number of tulips sold. Tulips were sold for $2 each and roses for $5 each. The club made $414.00. How many roses were sold?

Answer 1

In this question there are several information's of immense importance. They can be used to get the required answer. It is given that the Math Club sold 8 more roses than 4 times the number of tulip[s. The cost of each Tulip was $2 and the cost of each rose was $5. Total amount gained is $414.
Now
Let us assume the number of roses sold = x
Number of Tulips sold = y
Then
x = 8 + 4y
5x + 2y = 414
Now if we replace the value of x from the first equation to the second equation we get:
5x + 2y = 414
5(8 + 4y) + 2y = 414
40 + 20y + 2y = 414
22y = 414 - 40
22y = 374
y = 374/22
= 17
Now putting the value of y in the first equation we get:
x = 8 + 4y
= 8 + 4(17)
= 8 + 68
= 76
So the Math Club sold 76 roses and 17 tulips.