Question

A 33 kg child on a swing has a potential energy of 720 J with respect to the ground. What is the child’s height above the ground? please answer soon

Answer 1

h = 2.22 m

Step-by-step explanation:

Using the international system, we know that the gravity of the earth is 9.8 m / s².

then, we have as data:

• Potential Energy (Ep) = 720 J
• Mass (m) = 33 kg
• Gravity (g) = 9.8 m/s²
• Height (h) = ?

Use formula:

• 
  `\boxed{h=(Ep)/(m*g)}`

Replace:

• 
  `\boxed{h=(720J)/(33kg*9.8(m)/(s^(2)))}`

Joules descompose:

• 
  `\boxed{h=(720N*m)/(33kg*9.8(m)/(s^(2)))}`

Solve the multiply of mass and gravity:

• 
  `\boxed{h=(720N*m)/(323.4kg*(m)/(s^(2)))}`

Multiply the units. Knowing that kg * m/s² = N, so:

• 
  `\boxed{h=(720N*m)/(323.4N)}}`

Simplify the Newtons (N), and it divides:

• 
  `\boxed{h=2.22\ m}`

What is the child’s height above the ground?

The child's height above the ground is 2.22 meters.