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The width of a rectangle is (x+1) and the length is (x-6). What is the length and width of the rectangle if the area is 30 square feet?

1 Answer

10 votes

Answer:

The length of the rectangle (l) = 3 feet

The width of the rectangle (W) = 10 feet

Explanation:

Step(i):-

Given that the width of the rectangle = (x+1) feet

Given that the length of the rectangle = ( x-6) feet

The area of the rectangle = 30 square feet

Step(ii):-

We know that the area of the rectangle

= length ×width

30 = ( x+1)(x-6)

30 = x² - 6x + x -6

⇒ x² - 5 x - 6 = 30

⇒ x² - 5 x - 6 - 30 =0

⇒ x² - 5 x - 36 =0

x² - 9 x +4x - 36 =0

x (x-9) +4 ( x-9) =0

( x+4 ) ( x-9) =0

( x+4 ) =0 and ( x-9) =0

x =-4 and x =9

Step(iii):-

we have to choose x =9

The length of the rectangle (l) = x-6 = 9-6 =3

The width of the rectangle (W) = x+1 = 9 +1 = 10

Final answer:-

The length of the rectangle (l) = 3 feet

The width of the rectangle (W) = 10 feet

User Sasha Pachev
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