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[2/SEC(¶/3)•[lim x→0 x^3+8x+10]^2]/[lim θ→0 sinθ/θ]
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Dec 7, 2016
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[2/SEC(¶/3)•[lim x→0 x^3+8x+10]^2]/[lim θ→0 sinθ/θ]
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Al Kasih
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Assuming the pilcrow is supposed to represent pi:
100
Gour
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Dec 12, 2016
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Gour
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