Question

2x2  + 6x + 5 = 0 what are the real roots for the quadratic equation  

Answer 1

`2x^2+6x+5=0\ \ \ \ /:2\\\\x^2+3x+2.5=0\\\\x^2+2x\cdot1.5=-2.5\\\\x^2+2x\cdot1.5+1.5^2-1.5^2=-2.5\\\\(x+1.5)^2-2.25=-2.5\\\\(x+1.5)^2=-2.5+2.25\\\\(x+1.5)^2=-0.25 < 0\ aren't\ real\ roots\ because\ for\ x\in\mathbb{R},\ a^2\geq0`

Answer 2

`2x^2 + 6x + 5 = 0`


`x= (-b+/- √(b^2 -4ac) )/(2a)`


`x= (-(6)+/- √((6)^2 -4(2)(5)) )/(2(2))`


`x= (-6+/- √(36 -40) )/(4)`


`x= (-6+/- √(-4) )/(4)`


`x= (-6+/- i√(4) )/(4)`


`x= (-6+/- 2i )/(4)`

NO REAL ROOTS