Question

The initial population of a town is 4500, and it grows with a doubling time of 10 years. What will the population be in 12 years

Answer 1

The future population of the town will be approximately 10338 after 12 years, calculated using the exponential growth formula, considering an initial population of 4500 and a doubling time of 10 years.

Step-by-step explanation:

The student is asking about the future population of a town that has an initial population of 4500 and experiences a doubling of its population every 10 years. To calculate the population after 12 years, we need to work with exponential growth. Since the doubling time is 10 years, we can use the formula for exponential growth P(t) = P0 * 2(t/D), where P(t) is the population at time t, P0 is the initial population, t is the number of years, and D is the doubling time.

The initial population, P0, is 4500, the time t is 12 years, and the doubling time D is 10 years. Plugging these values into the formula gives us:

P(12) = 4500 * 2(12/10) = 4500 * 21.2 ≈ 4500 * 2.2974 ≈ 10338

Therefore, the population of the town will be approximately 10338 after 12 years.

Answer 2

In the given problem, there are several vital informations that have been provided. based on these information's the answer to the asked question can be easily reached. It is given that the initial population of the town is 4500. It doubles in every 10 years. The number of population in 12 years is needed to be found.
Initial population of the town = 4500
In 10 years the population of the town = 4500 * 2
= 9000
Then population of the town in 12 years = (9000/10) * 12
= 10800
So the population of the town in 12 years will be 10800.