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What is a factor of the expression 250 x cubed - 16 y ^ 3

User Carlos Taylor
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1 Answer

14 votes
14 votes

Consider the given expression as,


250x^3-16y^3

The equation can be written as,


(\sqrt[3]{250}x)^3-(\sqrt[3]{16}y)^3

Use the algebraic identity,


a^3-b^3=(a-b)(a^2+ab+b^2)

Substitute the values and simplify,


(\sqrt[3]{250}x)^3-(\sqrt[3]{16}y)^3=(\sqrt[3]{250}x-\sqrt[3]{16}y)\mleft\lbrace(\sqrt[3]{250}x)^2+(\sqrt[3]{250}x)(\sqrt[3]{16}y)+(\sqrt[3]{16}y)^2\mright\rbrace

Thus, the factors of the given expression are,


(\sqrt[3]{250}x-\sqrt[3]{16}y)\text{ and }\lbrace(\sqrt[3]{250}x)^2\text{ and }(\sqrt[3]{250}x)(\sqrt[3]{16}y)+(\sqrt[3]{16}y)^2\rbrace

User Ralepinski
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2.4k points
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