192k views
18 votes
ABCD is a rectangle. If AC = 2x + 10 and BD = 56, find the value of x.

Group of answer choices

33

23

78

122
Help!

User Gomino
by
8.4k points

2 Answers

9 votes

Final answer:

The value of x in the rectangle problem where AC = 2x + 10 and BD = 56 is found to be 23, after solving the equation 2x + 10 = 56.

Step-by-step explanation:

The student has asked a geometry question involving a rectangle. In a rectangle, the diagonals are congruent, meaning that AC = BD. Given that AC = 2x + 10 and BD = 56, we can set up the equation 2x + 10 = 56. To find the value of x, we subtract 10 from both sides and get 2x = 46. Dividing both sides by 2 gives us x = 23. Therefore, the value of x is 23.

User Trekkie
by
8.5k points
8 votes

9514 1404 393

Answer:

(b) 23

Step-by-step explanation:

The diagonals of a rectangle are the same length, so ...

AC = BD

2x +10 = 56

x +5 = 28 . . . . . divide by 2

x = 23 . . . . . . . . subtract 5

User Silvestris
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories