Question

A spinner with three equal spaces of red, blue, and green is spun one time. A singlesix-sided die is rolled once. What is the probability that you get blue and a numbergreater than 3?

Answer 1

Probability = (number of favorable outcomes)/(total number of possible outcomes)

The number of sides that the spinner has is 3(total number of possible outcomes)

The number of blue sides is 1(number of favorable outcomes)

Probability of getting a blue = 1/3

For the die,

Total number of possible outcomes = 6

Number of favorable outcomes = numbers greater that 3(4, 5 and 6) = 3

Probability of getting a number greater than 3 is 3/6 = 1/3

Therefore, the probability that you get blue and a number greater than 3 is

1/3 * 1/3 = 1/9