In this question, we have to determine the molar concentration, or molarity of a CH3COOH solution.
We have as informations:
74 Liters of 0.643 M of KOH
33.1 Liters of CH3COOH
Although we have a situation of weak acid + strong base, the question provides informations considering a strong acid + strong base situation, so I will consider CH3COOH as a strong acid, even though IT IS NOT A STRONG ACID.
In order to find the molarity, we can use the Titration formula:
MaVa = MbVb
Ma = molarity of the acid
Va = volume of the acid
Mb = molarity of the base
Vb = volume of the base
Ma * 33.1 = 0.643 * 74
33.1Ma = 47.58
Ma = 1.44 M
The concentration of this acid, based on the information provided, will be 1.44 M