Question

Solve for x. 10x^2=29x-21 does anyone know this

Answer 1

`10x^2=29x-21 \\ 10x^2-29x+21=0\\ \Delta=(-29)^2-4\cdot10\cdot21=841-840=1\\ √(\Delta)=\sqrt1=1\\ x_1=(-(-29)-1)/(2\cdot10)=(28)/(20)=(7)/(5)\\ x_2=(-(-29)+1)/(2\cdot10)=(30)/(20)=(3)/(2)\\`