How do I solve for x and state the restriction if (a-c)/(x-a)=m

asked May 26, 2015 165k views

5 votes

by Binz

7.8k points

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5 votes

(a - c)/(x - a) = m

(x - a) (a - c)/(x - a) = m ( x - a)

a - c = mx - am

a - c + am = mx

(a)/(m) - (c)/(m) + (am)/(m) = x

(a - c)/(m) + a = x

Kenlly Acosta answered May 27, 2015

7.0k points

6 votes

$(a-c)/(x-a)=m;\ D:x\\eq a\\\\m(x-a)=a-c\\\\mx-ma=a-c\\\\mx=a-c+ma\ \ \ \ /:m\\eq0\\\\x=(a-c+ma)/(m)$

ZacharyP answered Jun 2, 2015

7.1k points

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