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Using A(x)=x(48-x) find the following: a.A(10) b.A(20) c.A(28) d.A(x)=0

User Chenglu
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1 Answer

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A(x) = x(-x + 48)
A(x) = x(-x) - x(48)
A(x) = -x² - 48x
A(10) = -(10)² - 48(10)
A(10) = -100 - 480
A(10) = -580

A(x) = x(-x + 48)
A(x) = x(-x) - x(48)
A(x) = -x² - 48x
A(20) = -(20)² - 48(20)
A(20) = -400 - 960
A(20) = -1360

A(x) = x(-x + 48)
A(x) = x(-x) - x(48)
A(x) = -x² - 48x
A(28) = -(28)² - 48(28)
A(28) = -784 - 1344
A(28) = -2128

A(x) = x(-x + 48)
A(x) = x(-x) - x(48)
A(x) = -x² - 48x
A(0) = -(0)² - 48(0)
A(0) = 0 - 0
A(0) = 0




User John Polo
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