Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Answer 1

C

Explanation:

x = (-5 +
`√(5)` )/2 , x = (-5 -
`√(5)` )/2

Answer 2

First we need to find delta for function ax2+bx+c = 0
DELTA = b2-4ac
DELTA = 25 -( 4*1*5)= 25 - 20 = 5

x1 = (-b-√DELTA)/2a = (-5 - √5)/2
x2 = (-b+√DELTA)/2a (-5+√5)/2
x1 and x2 are zeros of this function