Question

The yard behind Sandy's house is a rectangle in shape and has a perimeter of

72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what
is the area of the yard, in square feet?
a 36 ft^2
b. 144 ft^2
c. 243 ft^2
d. 486 ft^2

Answer 1

c. 243 ft^2

Explanation:

where l = length

w= width

given; l= w+18

perimeter= 2(l+w)

72= 2(l+w)

72/2 = l+w

36= l+w

36= (w+18) +w

36= w+w+18

36= 2w +18

36-18=2w

18=2w

18/2=w

w=9ft

l=w+18

l=9+18= 27ft

Area = l×w

= 27×9 = 243ft^2

Answer 2

Including results for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 x. 243 ft^2 d. 486 ft^2

Search only for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 c. 243 ft^2 d. 486 ft^2

Explanation:

Including results for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 x. 243 ft^2 d. 486 ft^2

Search only for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 c. 243 ft^2 d. 486 ft^2