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36 votes
36 votes
A minor league baseball team plays 80 games in a season. If the team won 17 more than twice as many games as they lost, how many wins and losses did the team have?How many games did the team lose?

User Neven Boyanov
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1 Answer

27 votes
27 votes

We know that

• There are 80 games in total.

,

• The team won 17 more than twice as they lost.

Each statement can be expressed as an equation.


w+l=80

Because there are 80 games in total.


w=17+2l

Now, we replace the second equation in the first one.


17+2l+l=80

We solve for l


\begin{gathered} 17+3l=80 \\ 3l=80-17 \\ l=(63)/(3)=21 \end{gathered}

Therefore, the team lost 21 games.

We use this value to find the games they won.


w=17+2(21)=17+42=59

Therefore, the team won 59 games.

User Dom Chapman
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