Question

How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?

Answer 1

from the formula of electric potential = (1/4πe)*(Qq/r), if one of the charge is doubled, the electric potential energy would be doubled too. Not so sure though, u might wanna double-check with someone else. But hope that helps. :)

Answer 2

Magnitude of potential energy is increased by factor "2"

Step-by-step explanation:

As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as

`U = (kq_1q_2)/(r)`

now we know that if the charge of one of the charge particle is increased to twice of initial charge then

`U' = (kq_1(2q_2))/(r)`

now we can say from above two equations that

`U' = 2U`

so on increase one of the charge to twice of initial value then the potential energy will become TWICE