Question

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge? 

Answer 1

5.6x1011 N

Step-by-step explanation:

I just got the wrong answer so here's the right one

Answer 2

In an electric field force,F= q₁q₂/4πε₀ r² (coulomb's law) as we know,F=qE E=F/q
E=q/4πε₀ r²
here,r= 0.0075 m
q= 0.0035 C
1/4πε₀ = 9×10⁹
E= 9×10⁹× 0.0035/(0.0075)²
=5.6 ×10¹¹ N/C