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What are the roots of the equation x^2+4x-16=0

User Marian I
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x^2+4x+16=0 \\ \\ \Delta=b^2-4ac \\ \Delta=4^2-4*1*16 \\ \Delta = 16-64 \\ \Delta=-48 \\ \Delta \ \textless \ 0 =\ \textgreater \ \text{we don't have REAL solutions} \\ \\ \text{but it can solve with the multitude of complex numbers }\mathbb{C}
User Sam Kong
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