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How to solve 2^(log(2)3+ log(2)5
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How to solve 2^(log(2)3+ log(2)5

User Mikle Garin
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2 Answers

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2^(\log_23+ \log_25 )=\\ 2^(\log_215)=\\ 15
User Rashkay
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2^(log_23+log_25)=2^(log_2(3\cdot5))=2^(log_215)=15\\\\---------------------------\\\\for\ a,b,c\in\mathbb{R^+}\\\\log_ab+log_ac=log_a(b\cdot c)\\\\a^(log_ab)=b
User Matthew Cline
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