Answer:
The equation of the straight line is 4x +y = 1
Explanation:
Step(i):-
Given points are (-1,5) and ( 2,-7)
Slope of the line

slope of the line m = -4
Step(ii):-
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
Final answer:-
The equation of the straight line is 4x +y = 1