Question

Interpret f(10)F(x)= 0.08x^3+x^2+x+0.26

Answer 1

The Solution:

Given the function:

`f(x)=0.08x^3+x^2+x+0.26`

We are asked to find and interpret f(10).

`f(10)=0.08(10^3)+(10^2)+(10)+0.26`
`\begin{gathered} f(10)=0.08(1000)+100+10+0.26=80+100+10+0.26 \\ f(10)=190.26 \end{gathered}`

Therefore, the correct answer is 190.26

This means when x=10, f(10)=190.26