Question

Factor.(6x+4) 3x + 22(x+2)2(3x+2)3(2x+1)

Answer 1

Step-by-step explanation

`\mathrm{Rewrite\: }6\mathrm{\: as\: }2\cdot\: 3`
`\mathrm{Rewrite\: }4\mathrm{\: as\: }2\cdot\: 2`
`=2\cdot\: 3x+2\cdot\: 2`
`\mathrm{Factor\: out\: common\: term\: }2`
`=2\mleft(3x+2\mright)`

In conclusion, the factored expression is 2(3x+2)