Question

I don't know why I can't think (maybe because its late) but can someone answer this along with a clear explanation? Thanks

Answer 1

`A=(0,1); \ \ \ B=(1,0)`


y = ax+b



`\pmb{1^(o)} \\ \\ \begin{cases} 1 = 0*a + b \\ 0 = 1*a + b \end{cases} \\ \\ \begin{cases} b = 1 \\ a+b = 0\end{cases} \\ \\ \begin{cases} b = 1 \\ a+1 = 0 \end{cases} \\ \\ \begin{cases} b = 1 \\ a = -1 \end{cases} \\ \\ \\ y = -x +1 \\ \\ y+x = 1 \\ \\ \boxed{4y+4x = 4}`




`\pmb{2^(o)} \\ \\ If \ A=(x_(1), y_(1)); \ \ \ B = (x_(2),y_(2)) \\ \\ (x_(2) - x_(1)) (y - y_(1))=(y_(2)-y_(1))(x -x_(1)) \\ \\ (1 - 0)(y - 1)=(0 - 1)(x - 0) \\ \\ y - 1 = -x \\ \\ y+x = 1 \\ \\ \boxed{4y+4x = 4}`